$y^8-256$
$12x^2-3x+4$
$log16\left(log8\left(x\right)\right)=\frac{3}{2}$
$6\left(2x^2-xy+4y^2\right)$
$\int\left(\tan\left(x\right)\cdot\left(\sec\left(x\right)+\tan\left(x\right)\right)\right)dx$
$5.\left(-8\right)=-40$
$2y^2+5y+2=0$
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