$\left(-2x^2\right)\cdot\left(5x^4y\right)$
$\frac{dy}{dx}=\frac{\left(x^2+2y^{2\:}\right)}{xy}$
$\frac{d}{dx}\left(\sqrt[4]{\frac{\left(5x+1\right)\left(x+4\right)^2}{\left(x^4+6\right)\left(x+7\right)}}\right)$
$8z^3-1$
$y'=\left(x-1\right)\left(y-2\right)$
$\left(4m-2\right)\left(4m+2\right)$
$\left(2x^3-9y^4\right)^2$
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