$\frac{dy}{dx}=\frac{3x-4}{3y}$

$\left(3y^2-2x+1\right)+\left(2x^2+2x+4\right)$

$2\sin\left(x\right)\cos^3\left(x\right)+2\sin^3\left(x\right)\cos\left(x\right)$

$\sin\left(2x\right)-\tan\left(x\right)\cos\left(x\right)=\tan\left(x\right)$

$y=\frac{x^2+2x}{x^3}$

$64x^2-160xy+100y^2$

$0+5-3+5-8+10+5-6$