$\sin=3$
$\int\left(8\left(2x-3\right)^2\right)dx$
$-2x\left(x-2\right)$
$2x^2-4x+1<\:0$
$\frac{dy}{dx}=-6x-30$
$7x-10<7x-20$
$\lim_{x\to\infty}\left(\frac{3x+1}{x}\right)$
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