$f\left(x\right)=\sqrt{x\left(4-x\right)}$
$2x^2-46x+240$
$\frac{dy}{dx}\left(4x^2+3y^2=1\right)$
$\frac{2-x}{4}<\frac{1}{3}$
$y^{''\:}-9y^'-22y=0$
$\left(\frac{1}{4}+3\right)^2$
$2\left(x+1\right)^2-4=x\left(x+3\right)$
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