$\int\frac{\sec^2\left(x\right)}{\left(5+2\tan\left(x\right)\right)^2}dx$

$4t\left(t-6\right)=-9$

$t\frac{dy}{dt}=\left(1+t\right)y$

$\int3y^4\sqrt{2-3y^5}dx$

$\int1\cdot ln\left(5x+1\right)dx$

$\lim_{x\to\infty}\left(\frac{1}{x}\cos\left(x^2-3\right)\right)$

$y'\:=2\left(y-x\right)$