$m^2=100$
$-4g^6-2g^6$
$-62\:68+8a$
$cotx=5$
$\lim_{x\to\frac{\pi}{2}}\left(\frac{\sin\left(4x\right)}{x}\right)$
$cot^2xsec^2x=cot^2x+1$
$2y^2+11y+18$
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