$\int_{9\:}^{\infty\:}\left(\frac{1}{\sqrt{x}}\right)dx$
$3.1416\cdot5cm$
$x^2+4x=6$
$4 + 5 - ( 3 - 5 ) + 6 + ( 2 + 3 )$
$x^2y-xy-8\:=\:-4$
$20x^2-20x+25$
$x^2-12x-28$
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