$\lim_{x\to\infty}\left(\frac{x^4-1}{lnx}\right)$
$\cos^2x+3\cos x+2=0$
$\lim_{x\to0}\frac{\ln\left(7x\right)}{\ln\left(6x\right)}$
$\int\frac{3x+2}{x^2-5x-6}dx$
$\frac{1}{2}a\text{restor}-\frac{3}{4}$
$100^2a+160ab+64b^2$
$x\left(a+4x\right)^{\frac{2}{2}}$
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