$f\left(x\right)=\sqrt{x^2+5x+6}$
$2\sin^2\left(x\right)-3\cos\left(x\right)$
$4m-3m+2m$
$\sqrt{6}\sqrt{8}$
$-2\:+\:\left(3\:-\:2\right)\:-\:\left[\left(4\:-\:3\right)\:-\:\left(-2\right)\right]$
$3x+5\ge2x-3$
$\frac{4x^4-40x^2-5x+25}{x+3}$
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