$3x+3=18$
$\frac{\cot\left(y\right)+\tan\left(y\right)}{\csc\left(y\right)}$
$2x\:+\frac{1}{2}x$
$\:x\:\left(\:x^2\:+\:1\:\right)^3$
$2.75x+2.25-1.5x+3$
$y'\:=\frac{-x}{y-2x}$
$\sqrt{-\frac{4}{5}}$
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