$\left(3\left(\infty\right)^2-5\left(\infty\right)+2\right)$
$\frac{dy}{dx}=-4y^5$
$440\left(2x-4\right)e^{x^2-4x+8}$
$\frac{d}{x^2+6x}$
$42x+14$
$5-x>-6$
$\frac{d}{dx}\left(\frac{\sin\left(5x\right)+\cos\left(5x\right)}{\sin\left(5x\right)-\cos\left(5x\right)}\right)^3$
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