$\left(\frac{3}{4}a^2+2b^3\right)^5$
$9x^3\:-\:6x^2\:+\:3x\:-\:3$
$\frac{5x-3}{x^3+2x^2-3}$
$\frac{\left(x+y\right)^2-z^2}{\left(x+y\right)+z}$
$319+1004+12.319$
$3\sin^2\left(x\right)-2=1$
$\frac{1}{cotx\left(1-cos2x\right)}=\csc\left(2x\right)$
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