$2x^3-2x^2+4x-4$
$\left(4b-3\right)\left(16b^2+12b+9\right)$
$\left(\frac{2}{3}x^2+\frac{1}{4}y^3\right)^'^2$
$1285.07-485.238$
$-2+2^3\cdot3^2$
$\left(3x^2+25\right)\left(3x^2-9\right)$
$\lim_{x\to\infty}\left(1+\frac{2}{n}\right)^n$
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