$y=\frac{dy}{dt}$
$\frac{\left(\frac{senx}{cosx}+\frac{cosx}{cotx}\right)}{cotx}$
$5\left(3\right)^3+7\left(3\right)^2+6\left(3\right)-1$
$\frac{x^3-4x^2-4x+2}{x+2}$
$3x^2+4x+6=0$
$2x+1+3x+2+4-x$
$7\left(-3y\right)$
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