$\lim_{x\to\infty}\left(\frac{2x^2+3x}{x^2-5}\right)$

$2y+\left(-1+5y\right)$

$\frac{dy}{dx}=\frac{\left(y-1\right)}{x^2-4x+4}$

$\frac{d}{dx}\left(3\tan\left(x\right)-\sec\left(x\right)\right)$

$27x^3+81x^2+81x+27$

$25.6036+148.3524+337.0896+67.8976+17.9776+0.2916+56.5504+184.4164+138.2976+248.3776$

$\left(3x\:^4\:y^2+\:3x^2\right)\:^2$