$3xdy=\left(\frac{3x^3}{y^2}-2y\right)dx$
$\lim_{x\to-1}\left(\frac{x^2+x-2}{x^2+4x+4}\right)$
$-321\:+\:\:-593$
$\frac{dy}{dx}\left(x^2y-2yx=6x-y+1\right)$
$2x^{2-2x+1}$
$\int\sqrt{3x+7}dx$
$\lim_{x\to3}\left(\frac{\ln\left(x+4\right)}{x-3}\right)$
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