$\frac{36}{2}-\frac{25}{1}$
$x+12<3x-8$
$\lim_{x\to-3}\left(\frac{x^3+2x-6x}{x^2+3x}\right)$
$\cos\left(x\right)\left(\cos\left(x\right)+\tan^2\left(x\right)\cos\left(x\right)\right)$
$\frac{d^2u}{dxdy}=u$
$\frac{x}{x^2+x}-\frac{1-x^2}{x^2-1}$
$x^4+3x^2-6$
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