$4x^3-\left(-\frac{3}{2}x^3\right)-\frac{4}{5}x^3$
$\left(4x-3\right)\left(2x^2+5\right)$
$y=lnx^{ln4x}$
$-10+\left(-3\right)\cdot4$
$\frac{d^2}{dx^2}\left(4x\cdot e^x\right)$
$\left(4\right)-2\:\left(4y\:-\:2\right)\:$
$\tan\left(5x\right)=10$
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