$\frac{x-3}{5}+\frac{2x+6}{2}\le\frac{x}{4}$
$\left(\frac{-7u}{w^2}\right)^2$
$-10b+b$
$y^6\:\cdot y^{-6}$
$25\:-\:16x^2$
$x+4=-2$
$\int\frac{\left(sen\left(u\right)+cos\left(u\right)\right)}{sen\left(u\right)\cdot cos\left(u\right)}$
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