$\left(4mn-8\right)^2$
$\int-6ce^cdc$
$\:\:\left(3x\:-\:7\right)\:\left(3x\:+\:7\right)\:\left(3x\:-\:7\right)$
$\left(13-a^2b^3\right)^2$
$r\frac{dv}{dr}=v^2+1$
$\frac{w}{3}=-2$
$6^4.\:2^3$
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