$\sqrt[3]{125}=\:$
$6x+3+10x^2-x^2$
$\left(5y\right)^2+13\left(5y\right)+42$
$\int\frac{\left(x^2\right)}{\left(x-4\right)\left(x+5\right)}dx$
$16x^2+12+36$
$\int\frac{x}{x^3+2x-x^2-2}dx$
$\int2x\cdot tan^{-1}\left(5x\right)dx$
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