$\frac{1\:+\:cos\:v\:}{1\:-\:cos\:v\:}=\:\frac{sec\:v\:+\:1}{sec\:v\:-1}$
$10+\left(-2\right)+4\cdot\left(-4\right)$
$\left(-8x+9\right)^2$
$\:\frac{5x^4}{x}$
$\sqrt{9x^2-18+5}$
$-4:-80$
$\frac{-x^3-x^2+3x+2}{x-2}$
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