$\frac{\sin\left(x\right)\cdot\cos\left(x\right)}{\cos\left(2x\right)}-\frac{\tan\left(x\right)}{1-\tan^2\left(x\right)}=0$

$4+1+2+3$

$10<2x$

$\frac{x^2+3x-3}{x+2}$

$csc\theta\:\left(sin\theta\:+\frac{cos^2\theta\:}{sin\theta\:}\right)$

$\frac{4x^2}{9}-6x^2+14$

$x^2-2x-7>5-x$