$5x^2-55x+10=0$
$-2x-x^2+1$
$\frac{x^3+6x^2+5x+4}{x^2-3x+1}$
$\:f\left(x\right)=\frac{x-3}{x^2-3x+2}$
$\left(\left(\left(-3\right)^2\right)^{-5}\right)^3$
$-\frac{4}{6}\cdot0.4$
$1977-13$
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