$5\left(-4\:+\:4x\right)$
$b^1$
$\sin^2x-cos^2x=2\sin^2x-1$
$2x+3<3-x$
$\lim_{x\to0}\left(\frac{in\:\left(1-8x\right)}{x}\right)$
$\int_0^{400}\left(4.8323x\right)dx$
$\int\frac{2x-1}{x^2-x+8}dx$
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