$\ln\left(2x+1\right)^2=6$
$\frac{1}{3}\log_k\left(x\right)+6\log_k\left(y\right)-4\log_k\left(x\right)$
$\left(3x-4\right)\left(2x^2+y-1\right)$
$x^2-5x-7=0$
$5\:x\:+12>\:\:10$
$\left(6x-7\right)-\left(6x^2-8x\right)$
$\left(a^4-2\right)^3$
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