$12^8\cdot12^{-6}$
$3\sqrt{2}x\:3\sqrt{6}$
$\frac{dy}{x^2dx}-cosy=0$
$\left(a-\frac{1}{a}\right)\left(a-\frac{1}{a}\right)$
$u^3+4u^2+4u$
$\frac{dy}{dx}=\frac{-y^2-1}{1+x^2}$
$-9=-x+12$
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