$\left(4x^2+y^3\right)\left(4x^2+y^3\right)$
$9x^2-42x+9$
$\frac{x^2-5x+6}{x^2-x-2}\cdot\frac{x^2+x-20}{x^2-3x+4}\:$
$\left(9xy^3+11z^4\right)^2$
$\frac{1}{x^3}-1$
$\left(2x^2+1\right)\left(3x-4\right)$
$17\:-\:-76$
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