$\lim_{x\to0}\left(\frac{3+x}{x}\right)$
$\left(3x^2y^0\right)\left(4x^0\right)$
$\left(6h^2+\frac{1}{4}k\right)^3$
$5x-8>x$
$\frac{6z}{z-6}+\frac{3}{z-1}=1$
$3tanx+2=8$
$300\cdot9$
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