$\frac{12m^5n^2}{3m^2n^2}$
$12y-6y^2-5$
$\int\left(\frac{\left(x^2-1\right)\left(x^2+1\right)}{x^2}\right)dx$
$y'-y=1+te^t;y\left(0\right)=0$
$\frac{2}{3}+x-6$
$9xy^2-7x^2y+x+5x^2$
$1.8^2$
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