$y=\ln\left(\frac{x^3e^{2x}}{3x^2+x-2}\right)$
$\left(3x^{a+2}-5y^{a-2}\right)^2$
$x^2-x^{-2}=0$
$2\sqrt{\frac{x^2}{2}+x+\frac{1}{2}}$
$\frac{d}{dx}3y^3-xy=4$
$\lim_{x\to\infty}\left(\frac{\ln\left(1+e^x\right)}{\sqrt{1+x^2}}\right)$
$\left(64x+48\right)^3$
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