$\lim_{x\to\infty}\left(2x^2+2x\right)^{\frac{1}{x^2}}$

$^{\left[\left(-32\right)+\left(-49\right)\right]}+\left[\left(+78\right)-\left(-28\right)-\left(-83\right)\right]$

$\frac{32y^3}{\left(y^2-5\right)^2}-\frac{32y}{y^2-5}-10y=0$

$-2\left(y-4\right)=\left(x-1\right)^{\left(2\right)}$

$\left(\frac{3}{5}m+\frac{1}{2\:}\right)\left(\frac{3}{5}m-\frac{1}{2\:}\right)$

$\lim_{x\to3}\left(\frac{5-5x^2}{4\tan\left(3x-3\right)}\right)$

$10x+8=8x+16$