$\lim_{x\to-1}\left(x^3-4x\right)$
$\frac{dy}{dx}=\frac{x+3y}{3x-y}$
$\frac{x-3}{x^2-3x}$
$\frac{3x^2+7x-1}{x+3}$
$\lim_{x\to2}\left(\frac{x^3-x^2-8x+12}{x^2-4x+4}\right)$
$-24\:+\:-1\:+\:16\:+\:0\:+\:-9$
$\frac{-x^4-x^2+7}{x^3+x^2+4x+4}$
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