$-\left(-2+6\right)$
$\infty^{-6}$
$\frac{dy}{dx}=\frac{x^5}{y^{-5}}$
$\left(\frac{1}{2}+3y\right)^2$
$\int\frac{\left(x+3\right)}{\sqrt[3]{x^2+6x}}dx$
$+20+21-32+18-15+3-2-9$
$xy\frac{dy}{dx}-y-2=0$
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