$\left(b\:2\:+3\right)\left(b\:2\:+2\right)=\:$
$\lim_{x\to0}\frac{3x}{2x+\sqrt{x^4-x^2}}$
$156-2\cdot\:-1\cdot\:11$
$\left(x-2\right)\cdot\left(y+8\right);\:x=2;\:y=1$
$16-5c+7c+3$
$40+x=5$
$\left(-2x+5\right)^2$
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