Simplifying
$\frac{4x-8}{3}<x+5$
$\int\left(x^2\left(7x^3+6\right)^6\right)dx$
$8m-3m+5m$
$5^{3-2x}=5^{-x}$
$\int2\left(t+12\right)^2dt$
$\frac{d}{dx}\frac{x+6}{x-2}$
$6\left(x^2-7x+12\right)$
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