$\int\left(5x^3\right)\left(x^3-1\right)^4dx$
$8\left(7g\right)+8g$
$-\left(2x+4\right)^2$
$2x-5\:=x$
$\frac{dc}{dx},\:e^{xc}=xyc$
$5x-7\le-12$
$x^2-9>0$
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