$\left(2+x^2\right)\left(4+x^6\right)$

$12x^2-6x+3$

$\left(4u^3+2\right)\left(5u^3+3\right)$

$\left(\frac{-1}{2}x^2y\right)\left(\frac{-3}{5}xy^2\right)\left(\frac{-10x^3}{3}\right)\left(\frac{-3}{4}x^2y\right)$

$\lim_{x\to\frac{9}{2}}\frac{2x^2-9x}{2x^2-x+6}$

$y=\left(x+2\right)^2\cdot\left(x-3\right)\:$

$x^2+\frac{-4}{x}+2$