$2\:x\:136$

$\lim_{x\to0}\frac{12.5^x-1}{x}$

$\lim_{x\to\infty}\left(\sqrt[3]{x^3-6x^2-x}\right)$

$\:m^3m^4\cdot\left(\frac{1}{2}\right)a^3$

$4\frac{\sec\left(x\right)\tan\left(x\right)+1-\tan^2\left(x\right)}{\sec\left(x\right)+\tan\left(x\right)}$

$\left[11x-9\right]>2$

$-8z-5z+2z-z$