$2x^2-6x+10$
$\sqrt[3]{\sqrt[5]{x^2}}$
$\frac{x^8+11x^4+20}{x^4+9}$
$\left(\sqrt{x}+\frac{1}{x^3}\right)^2$
$y'-4xy=0,\:y\left(0\right)=\frac{1}{5}$
$-3x\left(4-x\right)+x\left(x+1\right)$
$\lim_{x\to2}\left(\frac{8x-16}{4x-8}\right)$
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