$\int arc\:ctg\:\left(\frac{m}{2}\right)x\:dx$
$\int\:\frac{2x^3-14x^2+24x+3}{x^2-7x+12}dx$
$\left(t^2+t\right)\left(t\right)$
$4\cdot\frac{\left(-5\right)}{\left(-2\right)}$
$\frac{dy}{dx}=xe^x+\frac{y}{x}$
$\frac{dy}{dx}-4y=2xy$
$5x\left(z^3-2\right)+3y\left(z^3-2\right)$
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