$x^2+8x+5$
$8\left(x-8\right)\left(x+1\right)^2-9\left(x-8\right)^2\left(x+1\right)$
$\frac{1}{1-sin\:^2a}=1+\tan^2a$
$\left(-20x^4y^5\right)\left(3y^4\right)$
$\left(2x^4+5x^3\right)^2$
$\tan x+\cot x-\sec x\cdot\csc x=0$
$4-7-8-9-3+18$
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