$9\:.\:\left(\left(-2\right)^3+5\right).\frac{6^2}{18}$
$\int\left(x^9\cdot\cos\left(x^{10}\right)\right)dx$
$s6+12\ge9$
$-\int\left(x^{-3}\right)dx$
$-1^{23}$
$3\sec^{2}x+2\tan x-4=0$
$\frac{11}{2x-1},c=6$
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