$10x^2\:\left(\:8x^3\:-\:7x\:-\:6x^5\right)$
$\int\frac{x+3}{e^{2x}}dx$
$\frac{\cot\left(1\right)}{\tan\left(1\right)}$
$\frac{12x\:+\:8}{3x^2+4x}$
$8x^2\:+\:32x$
$3\left(6-4k\right)-5k$
$8x^2-2xy+y^2+x^2-xy+3y^2-x^2+3xy$
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