$\lim_{x\to0}\left(\frac{e^{x^2}-1}{x^2}\right)$
$18+x=27$
$\left(a+1\right)-7\left(a+1\right)$
$\left(4x\right)\left(2x^{-2}\right)$
$18\cdot3$
$\frac{5}{x-5}=\frac{x}{x-5}$
$2xy'+y=6x$
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