$\int\frac{x-9}{x^2-\:6x}dx$
$10+1+0.1+0.01$
$\left(a^2-6\right)^2$
$\frac{cos\left(x\right)-cos^2\left(x\right)}{sin^2\left(x\right)}=\frac{cos\left(x\right)}{1-cos\left(x\right)}$
$\left(x^{3-b}\right)^2$
$\frac{11a}{x^2-16a^2}+2$
$\left(2x^{0.5}+1\right)\left(2x^{0.5}-1\right)$
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