$\lim_{x\to8}\left(x^2+3\right)^2$
$\lim_{x\to\infty}\left(\frac{2x^2+3}{x^2-5x-1}\cdot2\right)$
$z+8z$
$x^{\frac{1}{3}}+y^{\frac{1}{3}}=a^{\frac{1}{3}}$
$\int\frac{2}{x\left(x+2\right)}dx$
$\frac{8x^3-4x^2+8}{x+2}$
$\frac{4x^3y^2}{7x}$
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