$\frac{w^8}{w^7}\cdot\frac{w^5}{w^2}$

$\sin^2\left(x\right)-\csc^2\left(x\right)=\cot^2\left(x\right)-\cos^2\left(x\right)$

$x'=x-t^2$

$\left(11-\frac{1}{y}\right)\left(-11+\frac{1}{y}\right)$

$\left(4v^2-5\right)^2$

$\frac{a^{12}-250b^{12}}{a^6+125b^6}$

$5a^2+15a+12=a^2-a-4$