$$x+x=\frac{y}{\frac{dy}{dx}}$$

$$\int\frac{1}{5}\tan3xdx$$

$$\left(a+2\right)^2\left(a-3\right)\left(a+3\right)$$

$$x^2\:+\:3y^2\:=\:3$$

$$-15-5x\le0$$

$$64x^2-49y^2$$

$$\left(\frac{1}{3}y\right)\left(\frac{1}{3}y\right)$$